lag
2015-10-16 14:47:10 18 举报yahoo~
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return
l1=1.0l2=0.0
l1=(l1*(t-x(j))*(t-x(j)))/((x(i)-x(j))*(x(i)-x(j))
子函数her
yes
y1=0.0
i≠j
l2=l2+1/(x(i)-x(j))
y1=y1+l1*(y(i)+(t-x(i))*(f(i)-2*l2*y(i)))
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