03牛顿迭代法

k=0

判断精度

return result

|x2-x1|< r

f'(x)=diff(expr)f''(x) = diff(f'(x))

x1 = y(x0)x2=y(x1)

result=x2

是

否

求一阶导和二阶导

y = x - f(x)/f'(x)

求迭代公式

f(x0)*f''(x0)< = 0

result = None

k = k+1

判断收敛性