List
pre
3
1
prev和cur两个指针循环移动
5
4
next
prev
Node *List
while(cur) { next = cur->next;//1 cur->next = pre; //2 pre = cur; //3 cur = next; //4}
loop
cur
2
next确保链表不断
X
Node *pre = NULL;Node *cur = List;Node *next = NULL;
