流程图2

dif2=s[j]-s[j-1]

dif1=dif2

dif2=-dif2

NO

j<n?

YES

dif1=-dif1

int dif1=s[1]-s[0]

i<n?

输入s[i]

dif2>0?

开始

dif1>0

dif1<dif2?

输出dif1