result.append(t);
false
builder.deleteCharAt(0);
获取两个多项式字符串
int a=in.nextInt(); int b=in.nextInt();
\"\".equals(result.toString())
(int i=0;in.hasNextInt();i++
true
输出当前多项式字符串
int i=entrys.length-1;i>=0;i--
获取两多项式之和
输出结果
t+=\"1\";
NOJ1005多项式加法
ture
a==0&&b==-1
int a=entrys[i];int b=i;处理字符串
Scanner in = new Scanner(System.in); int[] entrys=new int[100]; StringBuilder result = new StringBuilder();
result.length()>0&&result.charAt(0)=='+'
int n=0;n<2;n++
result.deleteCharAt(0);
结果处理
builder.charAt(0)=='+'
处理字符串
(a==1 || a==-1) && b==0
result=new StringBuilder(\"0\");
